) A 7.30-kg bowling ball strikes a 1.60-kg pin at rest head-on. Before the collision, the velocity of the ball is 6.00 m/s. After the collision, the velocity of the ball is 5.40 m/s. What is the velocity of the pin after the collision

The final velocity of the pin after the collision is  2.7 m/s.

The given parameters:

The final velocity of the pin after the collision is determined by applying  the principle of conservation of linear momentum;

Thus, the final velocity of the pin after the collision is  2.7 m/s.

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the velocity of the pin after the collision is 2.7 m/s

Explanation:

The computation of the velocity of the pin after the collusion is as follows:

Given that

Mass of the ball = M = 7.3 kg

Mass of pin = m = 1.6 kg

The Velocity of the ball prior collision =  U = 6 m/ s

The Velocity of the pin prior collision=  u =0

The Velocity of the ball after collision = V = 5.4 m/s

Based on the above information

As we know that

Here the conservation law respect to the linear momentum is applied

mu+ MU = mv + MV

0 + 43.8 = 1.6 v + 39.42

 1.6 v = 4.38

v = 2.7 m/s

Hence, the velocity of the pin after the collision is 2.7 m/s

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54 degrees incident angle = reflected angle

angle is from normal turned to line of ray