A particle moves with an initial velocity 37 m/s and accelerates for 51 m/s^2 . Determine its velocity after 6 seconds

The velocity after 6 seconds will be: v = 44.5 m/s

Explanation:

Initial velocity = u = 37 m/s

acceleration = a = 51 m/s²

Time = 6 seconds

Final velocity = v = ?

Using the equation of motion

v² = u²+2as

m/s

Therefore, the velocity after 6 seconds will be: v = 44.5 m/s

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