Physics, 22.12.2020 01:00, kenniedalany

A 5.0-cm-radius parallel-plate capacitor has a 5.0 mm gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?

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answered: wutwut2261

1.389×10^-5A

Explanation:

We can calculate the displacement current in the capacitor using the expresion below

J=Q/t(*)

t= time elapsed

W= stored charge in capacitor

But Q= CV(1)

C = capacitance across given capacitor

V =voltage across given capacitor.

But capacitance in parallel plate capacitor can be expressed vas

C= εA/d(2)

A = area of plates

d= distance between the plates= 5.0 mm gap.= 5×10^-3 m

ε= Vacuum permisivity= 8.85×10^-12F/m

If we input eqn (1) and (2) into eqn (*) we have the expression below

J= εAV/dt(4)

But ratio of V/t=500,000 V/s

But Area=πd^2/2

Where d= diameter= (2×radius)=(2×5cm)=10cm=0.1m

Area=[ π × (0.1)^2]/2

=0.0157m^2

If we substitute all these value into eqn(4) we have

J=[( 8.85×10^-12) × (0.0157)×(500,000)]/5×10^-3

J=1.389×10^-5A

Hence, the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s is 1.389×10^-5A

answered: Guest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

answered: Guest

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles

b) 0.4 miles

c) 1 mile

d) 3.15 miles