A spring has a spring constant of 120 N/m. How much energy is stored in the spring as it is stretched a distance of 0.20 meter?

2.4J

Explanation:

Given parameters:

Spring constant  = 120N/m

Extension  = 0.2m

Unknown:

Amount of energy  = ?

Solution:

The energy stored in this stretched spring is called the elastic potential energy.

It can be derived using the expression below:

 Elastic Potential energy  = ke²  

k is the elastic constant

e is the extension

  Insert the parameters;

        Elastic potential energy  =    x 120 x 0.2²  = 2.4J

multiple

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)