when jerome paddle in flowing river towards east the net speed of jerome will increase
so the net speed of jerome will be given as
![v_j = v_1 + v_2 = 3.100 + 1.350 = 4.45 m/s](/tex.php?f=v_j = v_1 + v_2 = 3.100 + 1.350 = 4.45 m/s)
now the speed of paul will be same as it is given as he is running on the ground
so
![v_p = 3.100 m/s](/tex.php?f=v_p = 3.100 m/s)
so here we can say since the speed of jerome is more so he will win the race
now as we know the distance so the time difference is given as
![\delta t = \frac{d}{v_j} - \frac{d}{v_p}](/tex.php?f=\delta t = \frac{d}{v_j} - \frac{d}{v_p})
![\delta t = \frac{2080}{4.450} - \frac{2080}{3.100}](/tex.php?f=\delta t = \frac{2080}{4.450} - \frac{2080}{3.100})
![\delta t = -203.55 s](/tex.php?f=\delta t = -203.55 s)
so jerome will reach first and the time difference will be 203.55 s or 3.4 min