A magnetic field (B=3.2x10^-3 T) passes perpendicular through a circular loop of wire ( radius= 5.0 cm) what is the magnetic flux through the hoop?

25.12 x 10^-6 T/m^2

Explanation:

Magnetic flux is

fi = B * A * cos theta

as filed passes perepndicular theta is 90degrees and cos theta is 1

B=3.2x10^-3 T

A = pi * r ^2

A = 3.14 * (0,05m )^2

A = 0,00785

A = 7,85 m 10^-3 m2

fi = 3.2x10^-3 T * 7,85 m 10^-3 m2

fi = 25.12 x 10^-6 T/m^2

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.

answer( sicar );