Janet jumps horizontally off a high diving platform with a velocity of 2.76 m/s and lands in the water 2.3 s later. How high is the platform? The acceleration of gravity is 9.8 m/s. Answer in units of m. How far from the base of the platform does she land? Answer and units of m.

(a) Let the height of the platform is h meter,

=>By s = ut + 1/2gt^2

=>h = 0 + 1/2 x 9.8 x (2.3)^2

=>h = 25.92 m

(b) By R = [Ux] x t

=>R = 2.47 x 2.3

=>R = 5.68 m

Explanation:

Explanation:

From the exercise we know the initial horizontal velocity and the time that Janet takes to land in the water

a) Knowing the formula for free falling objects, we can calculate how high is the platform

At t=2.3m the position of Janet is y=0m

So, the platform is 26m tall

b) According to dynamics the displacement of an object can be analyze using the following formula:

So, Janet lands 6 m far from the base of the platform

d.7.5cm is your answer

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