A typical road bike wheel has a diameter of 70 cm including the tire. In a time trial, when a cyclist is racing along at 12 m/s how fast is a point at the top of the tire moving?

The speed at which the point at the top of the tire moves is 24 m/s.

Given that,

Based on the above information, the calculation is as follows:

We know that the velocity of the point should be the twice of the object velocity.

So,  

= 2 (12)

= 24 m/s

Therefore we can conclude that the speed at which the point at the top of the tire moves is 24 m/s.

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24 m/s

Explanation:

Given that,

A typical road bike wheel has a diameter of 70 cm including the tire.

Speed of the cyclist = 12 m/s

We need to find the speed at the top of the tire moving. The velocity of the topmost point is twice that of the velocity of the object.

v = 2 × 12

= 24 m/s

Hence, the required velocity is 24 m/s.

double the distance = divide strength by 4

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form