A particle is moving with simple harmonic motion of period 8•0 s and amplitude 5•0 m Fine (A). The speed of the particle when it's 3•0 m from the centre of it's motion (B). The maximum speed (C). The maximum acceleration

Idon't know it i just need my points lol

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.