A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degrees with the verticle. In such a condition of static equillibrium what is the net force on the vine?

461.88 N  

Explanation:

Let tension in each vine be T .

The vertical component of this tension of both the vine will add up and balance the weight .

2T cos 30 = mg

2 T x cos 30 = 800

T  = 800 / (2 x cos30 )

= 461.88 N  

i think they are all correct

explanation:

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