(2) A 72 kg crate is on a freight elevator. It accelerates upwards at a rate of 0.2 m/s 2 while moving down. Determine the force of the cable on the elevator.

the force required to move the cart is divided by three or 33.33 n.

false br

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

answer///scientific method;