Will mark the brainliest A nail of mass ,7.0g is held horizontally and is hit by a hammer of mass 0.25kg moving at 10ms −1. The hammer remains in contact with the nail during and after the blow.

If velocity of nail and hammer immediately after the blow is 9.7ms-1 Calculate the impulse transferred to the nail

The impulse transferred to the nail is 0.01 kg*m/s.

Explanation:

The impulse (J) transferred to the nail can be found using the following equation:

Where:                                                                

: is the final momentum

: is the initial momentum

The initial momentum is given by:

Where 1 is for the hammer and 2 is for the nail.

Since the hammer is moving down (in the negative direction):

And because the nail is not moving:

Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:

Since the hammer and the nail are moving in the negative direction:

= = -9.7 m/s

Finally, the impulse is:

Therefore, the impulse transferred to the nail is 0.01 kg*m/s.

I hope it helps you!