A girl throws a ball vertically upwards. It takes a time of 3.20 s to return to her hand. Assume air resistance is negligible.
What is the initial speed with which the ball is thrown?

15.68ms

Explanation:

From the question, we are informed that it takes a time of 3.20s for the ball to return to her hand.

Then, the time thst will be taken by the ball to reach maximum height will be 1.6s

Let the initial speed be represented by v.

Therefore,

Vf = v - gt

where,

g = 9.8

t = 1.6

Vf = v - gt

0 = v - (9.8 × 1.6)

0 = v - 15.68

v = 15.68ms

=v−gt

⟹0=v−9.8×1.6

⟹v=15.68ms

the force required to move the cart is divided by three or 33.33 n.

this could be newton#'s law of cooling. the cooling curve is exponential