How much force is required to accelerate an 8 kg mass at 5 m/s? if there is 14 N of
friction?

I think that its c

Explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle