The body falls in a free fall 11s. Calculate: a) from what height the body of the paddle) what path did it fall during the last second of the paddle) what speed was it just before the impact

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

a)

We will use second equation of motion to find the height:

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

h = 593.50 m

b)

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

where,

h = height covered during last second = h₁₁ =  ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

h₁₁ = 103 m

c)

Now, we use first equation of motion for complete motion:

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

vf = 107.91 m/s

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.