A 20 N force to the right and a 5.0 N force to the left are simultaneously applied to an 8.0 kg object. What is the net force of the object?

A. F.100 N, right
b. G. 122 N. left
C. H. 25 N. left
d. J. 15 N, right

d. J. 15 N, right

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

20N force right

5N force left.

The net force is equal to the summation of all the forces in Newton

Net force= +20-5

Net force=+15N

The direction is right.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y