An object that is initially traveling at 17.6 m/s has 1,743 J of work performed on it. If the mass of the
object is 283 kg, its final kinetic energy will be
J.

v 154.9= 0.9 length length s little over 154.9cm

the assestment will probley apele with cause and effect

close lines strong magnet less close weaker

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s