A wagon moving down the road has 2000 kg m/s of momentum. Then a 500-kg bag of feed with no velocity is added to the wagon. What is the new momentum of the wagon with the feed bag in kg m/s?

The new momentum of the wagon with the feed bag is (also) 2,000 kg·m/s

Explanation:

The given momentum of the wagon = 2000 kg·m/s

The mass of the added bag = 500 kg

The initial velocity of the bag of feed = 0 m/s

Therefore, by the conservation of momentum principle, we have;

The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = The new momentum of the wagon with the feed bag

Which gives;

The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon  = 2,000 kg·m/s + 500 kg × 0 = 2,000 kg·m/s = The new momentum of the wagon with the feed bag

Therefore, the new momentum of the wagon with the feed bag = 2,000 kg·m/s.

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

the rearrangement of particles in a physical change. hope this