1) If a bus travelling at 20 m/s is subject to a steady deceleration of 5 m/s2, how long will it take to come to rest?

Bus will take 4 seconds before it comes to rest.

Explanation:

Initial Velocity  of bus = u = 20 ms⁻¹

Final Velocity of bus = v = 0 ms⁻¹

Deceleration of bus = a = -5 ms⁻²

Time taken by bus before it comes to rest = t = ?

Using the equation formula

a = (v - u)/t

-5 = (0 - 20) / (t)

t = -20/-5

t = 4 sec

Therefore, Bus will take 4 seconds before it comes to rest.

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