A gas occupies 11.2 liters at 0.860 atm. What is the pressure if the volume becomes is doubled? * 3 points Doubled Quadrupled Decreased by a factor of 4 Half as much as it was

Half as much as it was

Explanation:

According to Charles law

PV = k

P is the pressure

V is the volume

If PV= k, then P1V1= P2V2

P1 and P2 are the initial and final pressure respectively

V1 and V2 are the initial and final volume respectively

Given

V1 =11.2litres

P1 = 0.860atm

If the volume is doubled, V2 = 2(11.2) = 22.4litres

Get P2

P2 = P1V1/V2

P2 = 0.860×11.2/22.4

P2 = 0.860/2

P2 = P1/2 (since P1 =0.860)

P2 = 1/2 P1

Hence the pressure becomes halved if the volume is doubled

answer: good job it's all correct !

explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft