A Fraunhofer diffraction pattern is produced on a screen 1.30 m from a single slit. If a light source of 560 nm is used and the distance from the center of the central bright fringe to the first dark fringe is 5.30 * 10^-3 m, what is the slit width?

The value is

Explanation:

From the question we are told that

    The distance from the screen is  D =  1.30 m

    The wavelength of the light source is  

     The path difference is mathematically represented as  

Generally the path difference is mathematically represented as

Here m is 1 given that we are considering the first dark fringe

So  

=>    

=>    

=>    

answer and explanation;

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