3. You shoot an arrow horizontally from 1.40 m off the ground. If it lands 35.0 m away, a. What was it's final veritcal velocity
b.
How fast did it leave your bow horizontally?
before hitting the ground?
I

The final velocity is 5.24 m/s

The initial speed is 65.5 m/s

Explanation:

Horizontal Motion

When an object is launched horizontally with an initial speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

The vertical component of the velocity changes in time t because gravity makes the object fall at increasing speed given by:

The maximum horizontal distance traveled by the object can be calculated as follows:

Another useful formula allows us to calculate the distance traveled by the object in terms of time t:

a.

The time taken for the arrow to reach the ground can be calculated by solving the above equation for t:

Since y=1.40 m:

t = 0.53 s

The final vertical speed is:

The final velocity is 5.24 m/s

b)

The initial speed can be calculated by solving the following equation for v:

v = 65.5 m/s

The initial speed is 65.5 m/s

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