Physics, 07.12.2020 05:30, matthewlucas8613
A 25 Kg rock is sitting on a cliff that is 50 meters above the ground. If it fell off of the cliff, and all energy was conserved, what would be the velocity of the rock right before it hit the ground?
Answers: 1
![E_{pot}=25*9.81*50\\E_{pot}= 12262.5[J]](/tpl/images/0955/4784/0d524.png)
![v^{2} =\frac{E_{k}*2}{m}\\v=\sqrt{(2*12262)/25}\\v = 31.32 [m/s]](/tpl/images/0955/4784/7434e.png)
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A 25 Kg rock is sitting on a cliff that is 50 meters above the ground. If it fell off of the cliff,...
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