A ladder of length 10 m and mass 25 kg leans against a smooth wall such that it is at an angle of 57∘ to the horizontal.  A man of mass 70 kg stands at the point A marked in the diagram, a distance d from the foot of the ladder. The coefficient of friction between the ground and the ladder is 0.1. A)Find the magnitude of the normal reaction force N acting at the foot of the ladder.

B) What is the relationship between the magnitude of the friction F acting on the foot of the ladder, and the magnitude of the normal reaction R, acting at the top of the ladder. Write your answer as a mathematical equation (using the "=" sign) involving F and R

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.