Physics, 06.12.2020 20:50, joseenrique02

A heat engine operating between the temperatures T1 and T2 takes in Qı calories at
temperature T1 and gives up Q2 calories at
temperature T2. The efficiency of this heat
engine is
(Q1 - Q2)/Q2.
(Q1 - Q2)/Q1.
(T2 - T1/T2.
Q2/(Q1 - Q2).
O T1/(T1-T2).

Answers: 1

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A heat engine operating between the temperatures T1 and T2 takes in Qı calories at
temperatur...