How high does a rocket have to go above the earth's surface to be subject to a gravitational field from the earth that is 50.0 percent of its value at the earth's surface? A) 2.650 km
B) 3,190 km
C) 9.020 km
D) 12.700 km

A) 2.650 km

Explanation:

The relationship between acceleration of gravity and gravitational constant is:

---- (1)

Where

-- Radius of the earth.

From the question, we understand that the gravitational field of the rocket is 50% of its original value.

This means that:

For the rocket, we have:

Where r represent the distance between the rocket and the center of the earth.

Substitute 0.5g for g rocket

--- (2)

Divide (1) by (2)

Take square root of both sides

Make r the subject

Substitute

The distance (d) from the earth surface is calculated as thus;

--- approximated

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge