Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.50 L, 2.6 g/cm³; 0.25 L, 1.0 g/cm³; and 0.40 L, 0.80 g/cm³. What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 cm³. (Ignore the contribution due to the atmosphere.)

The force is  

Explanation:

From the question we are told that

    The number of liquids is  n =  3

      The volume of the first liquid is

      The density of the first liquid is  

      The volume of the second  liquid is

      The density of the second liquid is  

      The volume of the third  liquid is

      The density of the  third  liquid is  

Generally the force at the bottom of the container is mathematically represented  as

Here

Here    is the total mass of all the liquid which is mathematically represented as

=>        

=>        

So

=>  

=>    

=>    

0.55x745.7j and a calculator

c) up

hope this