Jim and Bob send a car careening off a cliff. The car has a velocity of 16 m/s when it went off the cliff and it lands 35 m from the base of the cliff. How long was the car in the air? How high is the cliff?

The time spent in air by the car is 2.19 s

The height of the cliff is 58.5 m

Explanation:

Given;

initial velocity of the car, u = 16 m/s

horizontal distance traveled, R = 35 m

The horizontal distance or range of a projectile is given as;

R = vt

where;

t is the time spent in air by the projectile

t = R/v

t = 35 / 16

t = 2.19 s

The height of the cliff is given as;

h = ut + ¹/₂gt²

h = (16 x 2.19) + ¹/₂(9.8)(2.19)²

h = 58.5 m

seeing the graph would