‼️can someone help me‼️ • What are the other two ways that you can rewrite the
formula F=ma?
• If I push a wheelbarrow, with a force of 240 N, with an
acceleration of 4 m/s2, how much mass does the
wheelbarrow have? (Solve using formula F=ma)

Part A:

The other two ways we can rewrite F = m·a are;

1) F = dp/dt

2) F = m × d(v)/dt

Part B:

The mass of the wheelbarrow is 60 kg

Explanation:

Part A:

The other two ways of rewriting the equation are;

1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and

2) From the above equation, where, m is constant, we have;

F = d(m·v)/dt  = m × d(v)/dt

∴ F = m × d(v)/dt

Part B:

The force with which we push the wheelbarrow = 240 N

The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²

From F = m × a

Where;

m = The mass of the wheelbarrow

m = F/a = 240 N/(4 m/s²) = 60 kg

The mass of the wheelbarrow = m = 60 kg.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)