A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between the tires and the road is only µ static = 0.188 and the kinetic friction coefficient is even lower, µ kinetic = 0.1316. The acceleration of gravity is 9.8 m/s². What is the shortest possible stopping distance for the car under such conditions? (neglect the reaction time of the driver and round your answer to 4 decimal places)

The shortest possible distance is  

Explanation:

From the question we are told that

   The mass of the car is  

    The speed along the horizontal road is  

     The static friction coefficient is  

      The kinetic friction coefficient is  

Generally the static frictional force acting on the car is  mathematically represented as

Generally the force propelling the car is mathematically represented as

Here a is the maximum acceleration

at the point which the car stops ,

=>

=>

=>

=>

Generally from kinematic equation

Here v  is the final velocity of the car and the value is zero given that the car comes to rest

So

=>    

=>    

explanation:

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