A baseball is thrown straight upward with a speed of 30 m/s. (a) How long will it rise? (6) How high will it rise? (c) How long after it leaves the band will it return to the starting point? (ch) When will its speed be
16 m/s?

(a) 3.06 s

(b) 45.92 m

(c) 6.12 s

(ch) 1.43 s

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

Similarly, the time it needs to reach the maximum height is:

The object's speed (vf) after time t is:

The baseball is thrown up at vo=30 m/s.

(a) It's required to calculate the time it needs to reach the maximum height:

(b) The maximum height is:

(c) The time needed to travel up is the same time required to return to the starting point:

(ch) The speed will be vf=16 m/s at a certain time. Using the equation

We solve for t:

t = 1.43 s

it has to be b, about 97 percent.