A long, rigid conductor, lying along the x-axis, carries a current of 7.0 A in the negative direction. A magnetic field B is present, given by B = 4.0i + 9.0x2 j , with x in meters and B in mT. Calculate the k-component of the force on the 2 m segment of the conductor that lies between x = 1.0 m and x = 3.0 m.

0.546

Explanation:

From the given information:

The force on a given current-carrying conductor is:

where the length usually in negative (x) direction can be computed as

Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:

where;

current I = 7.0 A

F = 546 × 10⁻³ T/mT

F = 0.546

answer; ///i believe that the correct answer is (45*) at a 45 degree check first good

false

explanation:

boats, things on boats luggage are way more heavy then water.