Giving brainiest to whoever can answer it for me with work.

Tension in the 55 degree cable  = 110.56 N

Tension in the 28.5 degree cable = 72.16 N

Explanation:

Decompose the two tensions T1 (on left cable) and T2(on right cable) in vertical and horizontal components using trigonometric functions sine and cosine. Then balance the forces in the vertical and in the horizontal as shown below:

Horizontal components acting on net horizontal force:

T1 cos(55) =T2 cos(28.5)

then  T1 = T2 (cos(28.5) / cos(55))

Vertical components acting on net vertical force:

T1 sin(55) + T2 sin(28.5) = 125

Now replace T1 with T2 (cos(28.5) / cos(55)) in the last equation:

T2 (cos(28.5) * sin(55)/ cos(55)) + T2 * sin(28.5) = 125

T2 ( cos(28.5) * tan(55) + sin(28.5)) = 125

solving for T2 we get: 72.16 N

now we use this T2 result in the substitution equation:

T1 = T2 (cos(28.5) / cos(55))

T1 = 110.56 N

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.