PLEASE ANSWER 15. A 20-kilogram monkey hangs from a tree limb by both arms. Draw a free-body diagram showing the forces on the monkey. Hint: 20 kilograms is not a force!

Farm = 98.1 [N]

Explanation:

To solve this problem we must draw the respective free body diagram, with the forces acting on the monkey. An analysis of the sums on the y-axis must be performed, in this axis the weight is acting down and the forces of both arms pulling up.

Weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

m = mass = 20 [kg]

g = gravity acceleration = 9.81 [m/s²]

W = 196.2 [N] (units of Newtons)

As this force points down, the force of both arms must go up, therefore each arm exerts a force of:

Farm = 196.2 / 2

Farm = 98.1 [N]

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.