A segment of wire of total length 3.0 m carries a 15-A current and is formed into a semicircle. Determine the magnitude of the magnetic field at the center of the circle along which the wire is placed. a. 1.6 mu T b. 4.9 mu T c. 1.0 mu T d. 9.8 mu T e. 15 mu T

c. 1.0 mu T

Explanation:

From, the ampere's  circuit law:

∫B.dl = μ₀ I

B.(2πr) = μ₀ I

where,

B = Magnetic Field = ?

r = radius of the circle = length of wire = 3 m

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

I = Current = 15 A

Therefore,

B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)

B = 10 x 10⁻⁷ T

B = 1 x 10⁻⁶ T = 1 μT

Hence, the correct option is:

c. 1.0 mu T

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation