A 0.900-V potential difference is maintained across a 1.5m length of 2 tungsten wire that has a cross-sectional area of 0.600 mm . What is the current in the wire?

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section,

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

So, the current in the wire is 6.42 A.

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