A ball dropped off of a cliff from rest takes 4.00 s to reach the bottom of the cliff. b. What is the velocity of the ball at the bottom of the cliff?
Given
Unknown
Equation
Solution

  39.2 m/s

Explanation:

Given:

  free-fall from rest for 4 seconds

Unknown:

  final velocity (v)

Solution:

  equation: v = at

The acceleration due to gravity is 9.8 m/s², so the velocity after 4 seconds will be ...

  v = (9.8 m/s²)(4 s) = 39.2 m/s

At the bottom of the cliff, the velocity of the ball will be 39.2 m/s.

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