Two carts of equal mass are on a horizontal, frictionless air track. Initially cart A is moving toward stationary cart B with a speed of va. The carts undergo an inelastic collision, and after the collision the total kinetic energy of the two carts is one-half their initial total kinetic energy before the collision. What is the speed of each cart after the collision?

v_{f} = v / 2

Explanation:

In this problem we will define a system formed by the two cars, in this case the forces during the collision are internal and the momentum is conserved.

Initial instant. Before the collision

        p₀ = m v

final instant. After the inelastic collision

        = (m + m) v_{f}

the moment is preserved

        p₀ = p_{f}

        m v = 2m v_{f}

        v_{f} = v / 2

since the cars have an inelastic collision the speed of the two vehicles is the same

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat