A ball is kicked off a 75 m tall cliff with a horizontal velocity of 5 m/s. How long till it reaches the ground? How far will the ball land from the base of the cliff?

Let, time taken is t.

So,

( Here, us is vertical component of initial velocity )

Now, distance covered from the base of the cliff is :

Therefore, time taken and distance covered is 3.873 s and 19.365 m.

Hence, this is the required solution.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

root word, prefixes, and suffixes