An airplane is attempting to drop relief supplies to a village. If the plane is flying at an altitude of 500m and a speed of 110 m/s, how far ahead of the drop zone does he need to release the pallet?'

1111 m

Explanation:

The following data were obtained from the question:

Height (h) = 500 m

Horizontal velocity (u) = 110 m/s

Horizontal distance (s) =?

Next we shall determine the time taken for the pallet to get to the target. This can be obtained as follow:

Height (h) = 500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

500 = ½ × 9.8 × t²

500 = 4.9 × t²

Divide both side by 4.9

t² = 500/4.9

Take the square root of both side.

t = √(500/4.9)

t = 10.1 s

Finally, we shall determine how far the pallet needs to be dropped in order to get to the target. This can be obtained as follow:

Horizontal velocity (u) = 110 m/s

Time (t) = 10.1 s

Horizontal distance (s) =?

s = ut

s = 110 × 10.1

s = 1111 m

Thus, the pallet must be dropped at a distance of 1111 m from the plane in order to get the target.

one "light year" is the distance that light travels, through vacuum, in one julian year.   that's 365.25 days, of 24 hours each.