You compress a spring by x, and then release it. Next you compress the spring by 2x. How much more work did you do the second time than the first

Work done is k.

Explanation:

The work done by the spring is the same as the potential energy stored in the spring.

So that,

work done = potential energy = k

where k is the spring constant of the material of the spring, and x is the compression.

When the spring is compressed by x;

work done = k

When the spring is compressed by 2x;

work done = k

                  = k(4)

                  = 2k

Therefore,

The work done the second time more than the first = 2k - k

                                                                                = k

The work done the second time more than the first is k.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂