6. The momentum of a 30.0 g bird with a speed of 12 m. s-1 is 0.36 kg. m.s-1. What will be its momentum 12s later if a constant .02 N force due to air resistance acts on it

Explanation:

initial momentum = .36 kg.m.s⁻¹

negative impulse = force x time = .02 x 12 = .24 kg.m.s⁻¹

final momentum - initial momentum = impulse

final momentum = initial momentum + impulse

= .36 - .24

= .12 kg.m.s⁻¹

hey , the answer is c

the answer is a 3.8cm

explanation: