You walk for a speed of 1.1 m/s (meters per second) for 6.0 seconds and then run in the same direction for 3.3m/s (meters per second) for another
6,0 seconds. What was your average speed for these 12 seconds? *

Average speed, As = 2.2 [m/s]

Explanation:

To solve these types of problems we must remember that the average of the speeds is determined by dividing the distance over time.

With the first speed and the time of 6 [s] we can calculate the distance.

V = x/t

where:

x = distance [m]

V = velocity = 1.1 [m/s]

t = time = 6 [s]

x1 = V*t

X1 = 1.1*6

X1 = 6.6 [m]

Now with the second velocity and  6 [s], we can calculate the second distance.

X2 = 3.3*6

X2 = 19.8 [m]

Now we have to calculate the average speed. The total distance is x = x1 +x2

X = 19.8 + 6.6 = 26.4 [m]

and the total time is 12 [s]

Therefore:

As = 26.4/12

As = 2.2 [m/s]

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

a electromagnetic waves