Ted Williams drops a ball from 12.7 meter to a desk that is 1.5 meter tall. What is the final speed of the ball right before it hits the desk?

Explanation:

Using the equation of motion

V² = u²+2g∆H

v is the final velocity

u is the initial velocity = 0m/s

g = 9.8m/s²

∆H = 12.7-1.5 = 11.2m

Substitute

v² =0²+2(9.8)(11.2)

v² = 219.52

v = √219.52

v = 14.82m/s

Hence the final.speed of the ball is 14.82m/s

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s