Physics, 13.11.2020 21:00, katiebaby4109
If mZWXY = 160°, what are m2WXZ and mZZXY?
2
Y
(5x+8)°
X
m2WXZ = 87° and mZZXY = 73°
m2WXZ = 94º and mZZXY = 78°
m2WXZ = 94º and mZZXY = 66°
m2WXZ = 78º and m2ZXY = 82°
Answers: 2
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Visualize the problem and identify special cases first examine the problem by drawing a picture and visualizing the motion. apply newton's 2nd law, ∑f⃗ =ma⃗ , to each body in your mind. don't worry about which quantities are given. think about the forces on each body: how are these consistent with the direction of the acceleration for that body? can you think of any special cases that you can solve quickly now and use to test your understanding later? one special case in this problem is if m2=0, in which case block 1 would simply fall freely under the acceleration of gravity: a⃗ 1=−gj^.
Answers: 1
If mZWXY = 160°, what are m2WXZ and mZZXY?
2
Y
(5x+8)°
X
m2WXZ = 87° and mZ...
Y
(5x+8)°
X
m2WXZ = 87° and mZ...
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