Physics, 11.11.2020 06:00, gumbyseth1969p45qjl
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answers: 1
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W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N nee...
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