A person who weighs 670 N steps onto a spring scale in the bath- room, and the spring compresses by 0.79 cm. (a) What is the spring con- stant

The spring constant is 84,810.13 N/m

Explanation:

Given;

applied force on the spring scale, f = 670 N

extention of the spring, x = 0.79 cm = 0.0079 m

Apply Hook's law to determine the spring constant;

f = kx

where;

f is the applied force

k is the spring constant

x is the is the extension

k = f / x

k = 670 / 0.0079

k = 84,810.13 N/m

Therefore, the spring constant is 84,810.13 N/m

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

ice to water 1 water to vapour 2 latent heat