the first vector is 27° with a force of 23 N. The second vector us 75° with a force of 30 N. Use 10 N = 1 cm as your scale. What is the resulting vectort The first vector is 224° with a force of 27 N. The second vector is 123°, with a force of 32 N. What is the resulting vector? In example C the first vector is 80° with a force of 16 N. The second vector is 144° with a force of 48 N. What is the force and degrees of the resulting vector?

The speed was not exceeded so it was slow

Answer8.0m;

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j