5. What is final temperature of the object with a heat capacity of 300 cal and a sp. Heat of 0.5 cal/g°C? The mass of the object is 200 g and the initial temperature is 0 degrees
Celsius.

3°C

Explanation:

Given parameters:

Heat capacity  = 300cal

Specific heat capacity  = 0.5cal/g°C

Mass of the object  = 200g

Initial temperature  = 0°C

Unknown:

Final temperature  = ?

Solution:

The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;

 Mathematically ;

        H  = m c x  (t₂ - t₁)

H is the heat capacity

m is the mass

c is the specific heat capacity

t is the temperature

  Insert the parameters and solve;

         300  = 200 x 0.5 x (t₂- 0 )

         100 t₂ = 300

              t₂ = 3°C

explanation:

newton's third law, for every action there is an equal and opposite reaction.

this means that the temperature of both substances will be equal