If a water balloon is launched with an initial velocity of 30.1 meters per second, at an angle of 24 degrees above horizontal, how much time will it take the balloon to reach the ground again? Please provide an explanation as well.

2.45 sec

Explanation:

use the equation:

a = (Vfy-Viy) / t a=-10m/sec sq

Viy = 30.1 Sin 24 = +12.24

Vfy = - Viy = -12.24

-10 = (-12.24-12.24)/t

t = 24.48/10= 2.45 sec

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right